2X^2+x-10=i

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Solution for 2X^2+x-10=i equation:


Simplifying
2X2 + x + -10 = i

Reorder the terms:
-10 + 2X2 + x = i

Solving
-10 + 2X2 + x = i

Solving for variable 'X'.

Move all terms containing X to the left, all other terms to the right.

Add '10' to each side of the equation.
-10 + 2X2 + 10 + x = 10 + i

Reorder the terms:
-10 + 10 + 2X2 + x = 10 + i

Combine like terms: -10 + 10 = 0
0 + 2X2 + x = 10 + i
2X2 + x = 10 + i

Add '-1x' to each side of the equation.
2X2 + x + -1x = 10 + i + -1x

Combine like terms: x + -1x = 0
2X2 + 0 = 10 + i + -1x
2X2 = 10 + i + -1x

Divide each side by '2'.
X2 = 5 + 0.5i + -0.5x

Simplifying
X2 = 5 + 0.5i + -0.5x

Reorder the terms:
-5 + X2 + -0.5i + 0.5x = 5 + 0.5i + -0.5x + -5 + -0.5i + 0.5x

Reorder the terms:
-5 + X2 + -0.5i + 0.5x = 5 + -5 + 0.5i + -0.5i + -0.5x + 0.5x

Combine like terms: 5 + -5 = 0
-5 + X2 + -0.5i + 0.5x = 0 + 0.5i + -0.5i + -0.5x + 0.5x
-5 + X2 + -0.5i + 0.5x = 0.5i + -0.5i + -0.5x + 0.5x

Combine like terms: 0.5i + -0.5i = 0.0
-5 + X2 + -0.5i + 0.5x = 0.0 + -0.5x + 0.5x
-5 + X2 + -0.5i + 0.5x = -0.5x + 0.5x

Combine like terms: -0.5x + 0.5x = 0.0
-5 + X2 + -0.5i + 0.5x = 0.0

The solution to this equation could not be determined.

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